Integrand size = 28, antiderivative size = 119 \[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\frac {2 c d (a+i a \tan (e+f x))^m}{f m}-\frac {i (c-i d)^2 \operatorname {Hypergeometric2F1}\left (1,m,1+m,\frac {1}{2} (1+i \tan (e+f x))\right ) (a+i a \tan (e+f x))^m}{2 f m}-\frac {i d^2 (a+i a \tan (e+f x))^{1+m}}{a f (1+m)} \]
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Time = 0.18 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3624, 3608, 3562, 70} \[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=-\frac {i (c-i d)^2 (a+i a \tan (e+f x))^m \operatorname {Hypergeometric2F1}\left (1,m,m+1,\frac {1}{2} (i \tan (e+f x)+1)\right )}{2 f m}+\frac {2 c d (a+i a \tan (e+f x))^m}{f m}-\frac {i d^2 (a+i a \tan (e+f x))^{m+1}}{a f (m+1)} \]
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Rule 70
Rule 3562
Rule 3608
Rule 3624
Rubi steps \begin{align*} \text {integral}& = -\frac {i d^2 (a+i a \tan (e+f x))^{1+m}}{a f (1+m)}+\int (a+i a \tan (e+f x))^m \left (c^2-d^2+2 c d \tan (e+f x)\right ) \, dx \\ & = \frac {2 c d (a+i a \tan (e+f x))^m}{f m}-\frac {i d^2 (a+i a \tan (e+f x))^{1+m}}{a f (1+m)}+(c-i d)^2 \int (a+i a \tan (e+f x))^m \, dx \\ & = \frac {2 c d (a+i a \tan (e+f x))^m}{f m}-\frac {i d^2 (a+i a \tan (e+f x))^{1+m}}{a f (1+m)}-\frac {\left (i a (c-i d)^2\right ) \text {Subst}\left (\int \frac {(a+x)^{-1+m}}{a-x} \, dx,x,i a \tan (e+f x)\right )}{f} \\ & = \frac {2 c d (a+i a \tan (e+f x))^m}{f m}-\frac {i (c-i d)^2 \operatorname {Hypergeometric2F1}\left (1,m,1+m,\frac {1}{2} (1+i \tan (e+f x))\right ) (a+i a \tan (e+f x))^m}{2 f m}-\frac {i d^2 (a+i a \tan (e+f x))^{1+m}}{a f (1+m)} \\ \end{align*}
Time = 0.79 (sec) , antiderivative size = 94, normalized size of antiderivative = 0.79 \[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\frac {(a+i a \tan (e+f x))^m \left (-i (c-i d)^2 (1+m) \operatorname {Hypergeometric2F1}\left (1,m,1+m,\frac {1}{2} (1+i \tan (e+f x))\right )+2 d (-i d m+2 c (1+m)+d m \tan (e+f x))\right )}{2 f m (1+m)} \]
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\[\int \left (a +i a \tan \left (f x +e \right )\right )^{m} \left (c +d \tan \left (f x +e \right )\right )^{2}d x\]
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\[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\int { {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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\[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\int \left (i a \left (\tan {\left (e + f x \right )} - i\right )\right )^{m} \left (c + d \tan {\left (e + f x \right )}\right )^{2}\, dx \]
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\[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\int { {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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\[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\int { {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (i \, a \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]
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Timed out. \[ \int (a+i a \tan (e+f x))^m (c+d \tan (e+f x))^2 \, dx=\int {\left (a+a\,\mathrm {tan}\left (e+f\,x\right )\,1{}\mathrm {i}\right )}^m\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^2 \,d x \]
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